Find average power by elevator motor? - how to find % w/w
A lift of 646 kg from the beginning of the rest. It moved into the living room of 3.98 s with constant acceleration until it reaches its cruising speed of 2.06 m / s. The gravitational acceleration 9.8 m / s \\ \\ \\ \\ is 2 u0026lt Find the average performance of the elevator motor during this period of acceleration delivered.
First, use vf = vi + get one, and I have a = 0.52 m / s 2 ^ Then I tried to find the force F = ma form for 334.36 N. Then I tried to find W (W = FX). How do I know if X. If d = v / t. I 173.06 Nm for the job. then P = W / t, I, 43.48. Is that correct?
Friday, February 12, 2010
How To Find % W/w Find Average Power By Elevator Motor?
Subscribe to:
Post Comments (Atom)
2 comments:
Hmm ...
You have to find the net force is F = ma F (334.36) less weight (W = mg, where g = 9.8)
At x with v ^ 2 = u ^ 2 + 2ax.
v = final = 2.06, r = 0, because of the peace, one that was calculated.
So x = (v ^ 2 - u ^ 2) / 2a.
Once used to find the resultant force on the distance multiplied by (x) to the average power of the engine.
Vf = Vo + sqrt (2 * a * x) to solve x
Xf = Xo + Vo * t + 0.5 solve * A * T ^ 2 for x
Post a Comment